Verify that y1(t) = 1 and y2(t) = t1/2 are solutions of the differential equationyy + (y)2 = 0 for t > 0. Then show that y = c1 + c2t1/2 is not, in general, a solution of thisequation. Explain why this result does not contradict Theorem 3.2.2

MATH 23 WEEK 1 INTRO TO DIFF EQ The simplest definition of a differential equation is that it is an unknown function described in terms of one or more of its derivatives. Ex 1: Newtonâ€™s second law of thermodynamics...