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# Prove: If is an orthonormal basis for , and if A can be expressed as then A is symmetric

ISBN: 9780470432051 396

## Solution for problem 20 Chapter 7.2

Elementary Linear Algebra: Applications Version | 10th Edition

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Elementary Linear Algebra: Applications Version | 10th Edition

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Problem 20

Prove: If is an orthonormal basis for , and if A can be expressed as then A is symmetric and has eigenvalues .

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Calc III Lec Day 1 8/29/16 Ch. 11.2 Vector : a set of ordered numbers Ex) vector a = (1,2,3) which does not equal (2,3,1) Uses 1. Locate points in space a. Vector a = (a ,1 ,2 )3means that from the origin (0,0,0) vector a terminates at point (a ,a1,a2) 3nd starts at point (0,0,0) 2. Vector Operations aka Algebra of Vectors a. Vector a = (a ,1 ,2 )3vector b = (b ,b 1b 2, 3 + b = (a- 1b ,1 +2 ,a2+b3) 3 b. Any number c times a vector a = (ca ,ca ,c1 ) 2 3 c. a + b = b + a 3. Diagonals of a Parallelogram a. For a parallelogram with adjacent sides formed by vectors a and b i. The long diagonal = a + b ii. The short dia

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##### ISBN: 9780470432051

This textbook survival guide was created for the textbook: Elementary Linear Algebra: Applications Version, edition: 10. Elementary Linear Algebra: Applications Version was written by and is associated to the ISBN: 9780470432051. The answer to “Prove: If is an orthonormal basis for , and if A can be expressed as then A is symmetric and has eigenvalues .” is broken down into a number of easy to follow steps, and 23 words. Since the solution to 20 from 7.2 chapter was answered, more than 221 students have viewed the full step-by-step answer. The full step-by-step solution to problem: 20 from chapter: 7.2 was answered by , our top Math solution expert on 03/13/18, 08:29PM. This full solution covers the following key subjects: . This expansive textbook survival guide covers 83 chapters, and 2248 solutions.

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