We know from Table 1 that similar matrices, A and B, have the same eigenvalues. However
Chapter 5, Problem 38(choose chapter or problem)
We know from Table 1 that similar matrices, A and B, have the same eigenvalues. However, it is not true that those eigenvalues have the same corresponding eigenvectors for the two matrices. Prove that if B = P 1 AP, and v is an eigenvector of B corresponding to the eigenvalue , then Pv is the eigenvector of A corresponding to .
Unfortunately, we don't have that question answered yet. But you can get it answered in just 5 hours by Logging in or Becoming a subscriber.
Becoming a subscriber
Or look for another answer