Calculate the wavelength of each frequency of electromagnetic radiation:
a. 100.2 MHz (typical frequency for FM radio broadcasting)
b. 1070 kHz (typical frequency for AM radio broadcasting) (assume four significant figures)
c. 835.6 MHz (common frequency used for cell phone communication)
Step-by-step solutionSolutionStep1a)False.Ionization energy is the energy required to remove the loosely bound valence electron froman isolated,gaseous atom.Its value is always positive because energy has to be given to anatom during the process of ionizationWhen energy is absorbed or given to an atom Eis positiveWhen energy is released Eis negative.Step2b)FalseAs we move along a period of the periodic table,size of the atoms decreases.Thus greaterenergy will be required to remove the outermost electron from its orbit.Consequentlyionization energy increases.Fluorine is found to the right of oxygen in the periodic table andthus Fluorine will have a greater ionization energy than oxygenStep3c)TrueSecond ionization energy will be greater than first ionization energy.This is because once youhave removed the first electron you are left with a positive ion. Trying to remove a negativeelectron from a positive ion is going to be more difficult than removing it from an atomStep4d)FalseThird ionization energy is the energy required to remove the third outermost electron fromthe atom .For an ion say X third ionization energy I will3e X2+ ---------------> X+ + e- ------> I (g) (g) 3It is not the energy needed to ionize three electrons.