The velocity of a 1.2-kg particle is given by v =1.5t3i + (2.4 3t2)j + 5k, where v is in

QUESTION:

The velocity of a 1.2-kg particle is given by \(\mathbf{v}= 1.5 t^3 \mathbf{i}+\left(2.4-3 t^2\right) \mathbf{j}+5 \mathbf{k}\), where \(\mathbf{v}\) is in meters per second and the time t is in seconds. Determine the linear momentum \(\mathbf{G}\) of the particle, its magnitude G, and the net force \(\mathbf{R}\) which acts on the particle when \(t=2 \mathrm{~s}\).