In a cylindrical pipe where area isnt constant, Equation 16.5 takes the form Use this

Chapter 16, Problem 70

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In a cylindrical pipe where area isnt constant, Equation 16.5 takes the form Use this equation to show that the heat-loss rate from a cylindrical pipe of radius and length L is where the pipe is surrounded by insulation of outer radius and thermal conductivity k and where and are the temperatures at the pipe surface and the outer surface of the insulation, respectively. (Hint: Consider the heat flow through a thin section of pipe, with thickness as shown in Fig. 16.16. Then integrate.)

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