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Two thin rods (each of mass 0.20 kg) are joined together
Chapter , Problem 100(choose chapter or problem)
Two thin rods (each of mass 0.20 kg) are joined together to form a rigid body as shown in Fig. 10-60. One of the rods has length \(L_{1}=0.40 \mathrm{~m}\), and the other has length \(L_{2}=0.50 \mathrm{~m}\). What is the rotational inertia of this rigid body about
(a) an axis that is perpendicular to the plane of the paper and passes through the center of the shorter rod and
(b) an axis that is perpendicular to the plane of the paper and passes through the center of the longer rod?
Questions & Answers
QUESTION:
Two thin rods (each of mass 0.20 kg) are joined together to form a rigid body as shown in Fig. 10-60. One of the rods has length \(L_{1}=0.40 \mathrm{~m}\), and the other has length \(L_{2}=0.50 \mathrm{~m}\). What is the rotational inertia of this rigid body about
(a) an axis that is perpendicular to the plane of the paper and passes through the center of the shorter rod and
(b) an axis that is perpendicular to the plane of the paper and passes through the center of the longer rod?
Step 1 of 4
We will use parallel axis theorem to solve this problem.
Parallel axis theorem states that the moment of inertia about an axis parallel to axis passing through its centre of mass is given by:
\(I=I_{\text {com }}+m h^{2}\)
Here, h is the distance of the parallel axis from the axis through centre of mass.