The magnetic field inside a solenoid of circular cross section is given by B S = bt k n
Chapter 27, Problem 50(choose chapter or problem)
The magnetic field inside a solenoid of circular cross section is given by B S = bt k n, where b = 2.1 T/ms. At time t = 0.40 s, a proton is inside the solenoid at x = 5.0 cm, y = z = 0, and is moving with velocity v ! = 4.8nj Mm/s. Find the electromagnetic force on the proton
Unfortunately, we don't have that question answered yet. But you can get it answered in just 5 hours by Logging in or Becoming a subscriber.
Becoming a subscriber
Or look for another answer