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Equations of lines Find an equation of the lines with the

Calculus: Early Transcendentals | 1st Edition | ISBN: 9780321570567 | Authors: William L. Briggs, Lyle Cochran, Bernard Gillett ISBN: 9780321570567 2

Solution for problem 3RE Chapter 1

Calculus: Early Transcendentals | 1st Edition

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Calculus: Early Transcendentals | 1st Edition | ISBN: 9780321570567 | Authors: William L. Briggs, Lyle Cochran, Bernard Gillett

Calculus: Early Transcendentals | 1st Edition

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Problem 3RE

Equations of lines Find an equation of the lines with the following properties. Graph the lines. a. The line passing through the points (2, ?3) and (4, 2) b. The line with slope ? and x? -intercept (?4, 0) c. The line with intercepts (4, 0) and (0, ?2)

Step-by-Step Solution:

Step-by-step solution Step 1 a) We need to find the equation of the line passing through the points (2, -3) and (4, 2). Step 2 To solve the problem, we use the Point-Slope Form of the equating of a line yy =1m(xx ) [1]1 with slope = m = y21 [2] x21 Step 3 Substituting [2] into [1], we get: yy = ( y21)(xx ) [3] 1 x21 1 Step 4 Using the given points (2, -3) and (4, 2) and [3] to find the equation of the line, we get: 2(3) y(3) = ( 42 )(x2) [4] Step 5 Simplifying and rearranging [4] i nto lope-Intercept Form, we get: y+3 = (x2) 2 y = x8 2 Step 6 Therefore, the equation for the line passing through the points (2, -3) and (4, 2) is: 5 y = x28 The graph of the function is shown below: Step 7 3 b) We need to find the equation of the line with slope 4 and x-intercept (-4, 0). Step 8 To solve the problem, we use the P oint-Slope Form of the equating of a line. yy = 1(xx ) [5] 1 Step 9 3 Using the given slope , x4intercept (-4, 0) and [5] to find the equation of the line, we get: y(0) = (x(4)) [6] 4

Step 10 of 17

Chapter 1, Problem 3RE is Solved
Step 11 of 17

Textbook: Calculus: Early Transcendentals
Edition: 1
Author: William L. Briggs, Lyle Cochran, Bernard Gillett
ISBN: 9780321570567

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