Explain geometrically how the Midpoint Rule is used to

Calculus: Early Transcendentals | 1st Edition | ISBN: 9780321570567 | Authors: William L. Briggs, Lyle Cochran, Bernard Gillett

Problem 2E Chapter 7.6

Calculus: Early Transcendentals | 1st Edition

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Calculus: Early Transcendentals | 1st Edition | ISBN: 9780321570567 | Authors: William L. Briggs, Lyle Cochran, Bernard Gillett

Calculus: Early Transcendentals | 1st Edition

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Problem 2E

Explain geometrically how the Midpoint Rule is used to approximate a definite integral.

Step-by-Step Solution:

SOLUTIONStep 1In midpoint formula we divide the interval [a,b] into n subintervals of equal width.Therefore we get We shall denote each of the subintervals as Where For each interval let .we then draw the graph for each subinterval...

Step 2 of 3

Chapter 7.6, Problem 2E is Solved
Step 3 of 3

Textbook: Calculus: Early Transcendentals
Edition: 1
Author: William L. Briggs, Lyle Cochran, Bernard Gillett
ISBN: 9780321570567

The full step-by-step solution to problem: 2E from chapter: 7.6 was answered by Sieva Kozinsky, our top Calculus solution expert on 03/03/17, 03:45PM. This full solution covers the following key subjects: approximate, Definite, explain, geometrically, integral. This expansive textbook survival guide covers 85 chapters, and 5218 solutions. Since the solution to 2E from 7.6 chapter was answered, more than 256 students have viewed the full step-by-step answer. The answer to “Explain geometrically how the Midpoint Rule is used to approximate a definite integral.” is broken down into a number of easy to follow steps, and 13 words. This textbook survival guide was created for the textbook: Calculus: Early Transcendentals, edition: 1. Calculus: Early Transcendentals was written by Sieva Kozinsky and is associated to the ISBN: 9780321570567.

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