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An object undergoing simple harmonic motion takes 0.25 s
Chapter , Problem 1(choose chapter or problem)
An object undergoing simple harmonic motion takes 0.25 s to travel from one point of zero velocity to the next such point. The distance between those points is 36 cm. Calculate the (a) period, (b) frequency, and (c) amplitude of the motion.
Questions & Answers
QUESTION:
An object undergoing simple harmonic motion takes 0.25 s to travel from one point of zero velocity to the next such point. The distance between those points is 36 cm. Calculate the (a) period, (b) frequency, and (c) amplitude of the motion.
ANSWER:Step 1 of 4
Simple harmonic motion is a type of periodic motion in which an object oscillates back and forth around an equilibrium position, with a motion that is characterized by a sinusoidal pattern.
The motion of the object is governed by a restoring force that is proportional to the displacement from the equilibrium position, and is directed towards the equilibrium position. This restoring force causes the object to oscillate back and forth, with a frequency that is determined by the mass of the object and the strength of the restoring force.
The time period is defined as the time taken for one complete oscillation. For a complete oscillation, an object travels from one point of zero velocity to the next such point and comes back to the original point.