(III) A door 2.30 m high and 1.30 m wide has a mass of 13.0 kg. A hinge 0.40 m from the top and another hinge 0.40 m from the bottom each support half the door's weight (Fig. 9-69). Assume that the center of gravity is at the geometrical center of the door, and determine the horizontal and vertical force components exerted by each hinge on the door.
Step 1 of 5 ^
FAx; x components of the force at hinge A
FAy; y components of the force at hinge A
FBx; x components of the force at hinge B
FBy; y components of the force at hinge B
M.g: the weight of the directed downward from the center of mass of the door.
H=2.30m the height of the door.
w=1,30m : the width of the door
d=40cm=0.4m the distance from the ends of the door to the hinges.
Step 2 of 5 ^
We are going to write the torques around hinge A.
Step 3 of 5 ^
We can write the first condition of equilibrium on x axis to find FAx