(II) Redo Example 9-9, assuming now that the person is

Step-by-step solution Step 1 of 3The angular momentum of an object about an axis of rotation is measured by theproduct of the linear momentum of the object and the perpendicular distancebetween the object and the axis of rotationSuppose an object of mass m is revolving around a circle of radius r with speed vabout an axis passing through center O as shown in the figure.The linear momentum of the object, p = mv.The angular momentum of an object, L = linear momentum x perpendicular distancefrom the axis of rotation. or, L = p rTherefore, L = m v rSince v = r, where w is the angular velocity of the object, the angular momentum canbe written as L = m ( r) r 2or, L = m r The equations above are the expressions for the angular momentum of the body. It is avector quantity.Principle of conservation of angular momentum states that, If no external torque acts on a system, the total angular momentum of the systemremains constant.If I be the moment of inertia of a body about a given axis of rotation and w be itsangular velocity, then I = constant.\nThis equation represents the mathematical form of principle of conservation of angularmomentum.Step 1 of 5 We know that the torque acting on a system is equal to the time rate of change ofangular momentum of the system about that axis, i.e. = dL if no external torque acts on the system, =0 dT dL =0 , integrate equation dTWe get, L=constantOr I = constantI i =i f f\n