Problem P 3.6-2
The circuit shown in Figure P 3.6-2a has been divided into three parts. In Figure P 3.6-2b, the rightmost part has been replaced with an equivalent circuit. The rest of the circuit has not been changed. The circuit is simplified further in Figure 3.6-2c. Now the middle and rightmost parts have been replaced by a single equivalent resistance. The leftmost part of the circuit is still unchanged. (a) Determine the value of the resistance R1 in Figure P 3.6-2b that makes the circuit in Figure P 3.6-2b equivalent to the circuit in Figure P 3.6-2a. (b) Determine the value of the resistance R2 in Figure P 3.6-2c that makes the circuit in Figure P 3.6-2c equivalent to the circuit in Figure P 3.6-2b. (c) Find the current i1 and the voltage v1 shown in Figure P 3.6-2c. Because of the equivalence, the current i1 and the voltage v1 shown in Figure P 3.6-2b are equal to the current i1 and the voltage v1 shown in Figure P 3.6-2c. Hint: 24 6(i12) i1R2 (d) Find the current i2 and the voltage v2 shown in Figure P 3.6-2b. Because of the equivalence, the current i2 and the voltage v2 shown in Figure P 3.6-2a are equal to the current i2 and the voltage v2 shown in Figure P 3.6-2b. Hint: Use current division to calculate i2 from i1. (e) Determine the power absorbed by the 3-V resistance shown at the right of Figure P 3.6-2a. i1 (a) i2 v2 v1 + + + 6 12 6 6 3 8 4 24 V 2 A v1 v2 R1 ( b) i2 i1 + + + 6 8 24 V 2 A 12 6 v1 R2 (c) i1 + + 6 24 V 2 A Figure P 3.6-2

Step-by-Step Solution:
Step 1 of 3
1. Mutual Exclusion Condition The resources involved are non-shareable. Explanation: At least one resource (thread) must be held in a non-shareable mode, that is, only one process at a time claims exclusive control of the resource. If another process requests that resource, the requesting process must be delayed until the resource has been released. 2. Hold and Wait Condition Requesting process...

Introduction to Electric Circuits was written by and is associated to the ISBN: 9781118477502. The full step-by-step solution to problem: P 3.6-2 from chapter: 3.6 was answered by , our top Engineering and Tech solution expert on 03/14/18, 07:39PM. This textbook survival guide was created for the textbook: Introduction to Electric Circuits, edition: 9. This full solution covers the following key subjects: . This expansive textbook survival guide covers 146 chapters, and 1397 solutions. The answer to “The circuit shown in Figure P 3.6-2a has been divided into three parts. In Figure P 3.6-2b, the rightmost part has been replaced with an equivalent circuit. The rest of the circuit has not been changed. The circuit is simplified further in Figure 3.6-2c. Now the middle and rightmost parts have been replaced by a single equivalent resistance. The leftmost part of the circuit is still unchanged. (a) Determine the value of the resistance R1 in Figure P 3.6-2b that makes the circuit in Figure P 3.6-2b equivalent to the circuit in Figure P 3.6-2a. (b) Determine the value of the resistance R2 in Figure P 3.6-2c that makes the circuit in Figure P 3.6-2c equivalent to the circuit in Figure P 3.6-2b. (c) Find the current i1 and the voltage v1 shown in Figure P 3.6-2c. Because of the equivalence, the current i1 and the voltage v1 shown in Figure P 3.6-2b are equal to the current i1 and the voltage v1 shown in Figure P 3.6-2c. Hint: 24 6(i12) i1R2 (d) Find the current i2 and the voltage v2 shown in Figure P 3.6-2b. Because of the equivalence, the current i2 and the voltage v2 shown in Figure P 3.6-2a are equal to the current i2 and the voltage v2 shown in Figure P 3.6-2b. Hint: Use current division to calculate i2 from i1. (e) Determine the power absorbed by the 3-V resistance shown at the right of Figure P 3.6-2a. i1 (a) i2 v2 v1 + + + 6 12 6 6 3 8 4 24 V 2 A v1 v2 R1 ( b) i2 i1 + + + 6 8 24 V 2 A 12 6 v1 R2 (c) i1 + + 6 24 V 2 A Figure P 3.6-2” is broken down into a number of easy to follow steps, and 294 words. Since the solution to P 3.6-2 from 3.6 chapter was answered, more than 249 students have viewed the full step-by-step answer.