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A band-stop filter has two cutoff frequencies, oa and ob. Suppose that oa is quite a bit

Introduction to Electric Circuits | 9th Edition | ISBN: 9781118477502 | Authors: James A. Svoboda, Richard C. Dorf ISBN: 9781118477502 422

Solution for problem P16.3-7 Chapter 16.3

Introduction to Electric Circuits | 9th Edition

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Introduction to Electric Circuits | 9th Edition | ISBN: 9781118477502 | Authors: James A. Svoboda, Richard C. Dorf

Introduction to Electric Circuits | 9th Edition

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Problem P16.3-7

A band-stop filter has two cutoff frequencies, oa and ob. Suppose that oa is quite a bit smaller than ob, say oa < ob/10. Let HL(s) be a low-pass transfer function having a cutoff frequency equal to oa and HH(s) be a high-pass transfer function having a cutoff frequency equal to ob. A band-stop transfer function can be obtained as a sum of low-pass and high-pass transfer functions, HN(s) HL(s) HH(s). The order of the band-pass filter is equal to the sum of the orders of the low-pass and high-pass filters. We usually make the orders of the lowpass and high-pass filter equal, in which case, the order of the band-stop is even. The pass-band gains of both the low-pass and high-pass transfer functions are set equal to the pass-band gain of the band-stop filter. Obtain the transfer function of a fourthorder band-stop filter having cutoff frequencies equal to 100 rad/s and 2000 rad/s and a pass-band gain equal to 2.

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Day 12 ­A while loop will only execute when the conditions are met ­Golden rule for while loops: your variable has to change within the loop ­First line is while(condition); last line is end ­If you are stuck in a loop, do Ctrl + C Write a code for how long it will take to pay back the...

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Chapter 16.3, Problem P16.3-7 is Solved
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Textbook: Introduction to Electric Circuits
Edition: 9
Author: James A. Svoboda, Richard C. Dorf
ISBN: 9781118477502

Since the solution to P16.3-7 from 16.3 chapter was answered, more than 205 students have viewed the full step-by-step answer. The answer to “A band-stop filter has two cutoff frequencies, oa and ob. Suppose that oa is quite a bit smaller than ob, say oa < ob/10. Let HL(s) be a low-pass transfer function having a cutoff frequency equal to oa and HH(s) be a high-pass transfer function having a cutoff frequency equal to ob. A band-stop transfer function can be obtained as a sum of low-pass and high-pass transfer functions, HN(s) HL(s) HH(s). The order of the band-pass filter is equal to the sum of the orders of the low-pass and high-pass filters. We usually make the orders of the lowpass and high-pass filter equal, in which case, the order of the band-stop is even. The pass-band gains of both the low-pass and high-pass transfer functions are set equal to the pass-band gain of the band-stop filter. Obtain the transfer function of a fourthorder band-stop filter having cutoff frequencies equal to 100 rad/s and 2000 rad/s and a pass-band gain equal to 2.” is broken down into a number of easy to follow steps, and 161 words. This textbook survival guide was created for the textbook: Introduction to Electric Circuits, edition: 9. The full step-by-step solution to problem: P16.3-7 from chapter: 16.3 was answered by , our top Engineering and Tech solution expert on 03/14/18, 07:39PM. Introduction to Electric Circuits was written by and is associated to the ISBN: 9781118477502. This full solution covers the following key subjects: . This expansive textbook survival guide covers 146 chapters, and 1397 solutions.

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