The Rayleigh distribution from Example 5.1.7 has PDF f(x) = xex2/2 , x> 0. Let X have
Chapter 5, Problem 54(choose chapter or problem)
The Rayleigh distribution from Example 5.1.7 has PDF f(x) = xex2/2 , x> 0. Let X have the Raylei distribution (a) Find E(X) without using much calculus, by interpreting the integral in terms of known results about the Normal distribution. (b) Find E(X2). Hint: A nice approach is to use LOTUS and the substitution u = x2/2, and then interpret the resulting integral in terms of known results about the Exponential distribution.
Unfortunately, we don't have that question answered yet. But you can get it answered in just 5 hours by Logging in or Becoming a subscriber.
Becoming a subscriber
Or look for another answer