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A piano tuner hears one beat every 2.0s when trying to
Chapter 13, Problem 39P(choose chapter or problem)
Problem 39P
A piano tuner hears one beat every 2.0s when trying to adjust two strings, one of which is sounding 440 Hz. How far off in frequency is the other string?
Questions & Answers
QUESTION:
Problem 39P
A piano tuner hears one beat every 2.0s when trying to adjust two strings, one of which is sounding 440 Hz. How far off in frequency is the other string?
ANSWER:
Solution 39PIntroductionWe have to first calculate the energy required to rise water’s temperature to the boiling pointand then we have to calculate the energy required for phase change.SolutionStep 1Required energy to increase the temperature is given byQ = meT 1Where m is the mass, c is the specific heat and T is the change in temperature of thewater.Here we havem = 100 gc = 1 g/calThe initial temperature of the water is 20 and the final temperature is boiling point ofwater, that is, 100. So the change in temperature is T = (100 20) = 80.So the required heat isQ 1 (100 g)(1 g/cal/)(80) = 8000 cal