The mean distance from the earth to the sun is 9.3 _ 107 mi. What is this distance in kilometers? in centimeters?
Step 1 of 3
Coupled Reactions • ex. Cu2S(s)—>2Cu(s) + S(s) —∆Grxn=86.2 kJ and ∆Hrxn=76.3 kJ, reaction is non spontaneous and can’t happen at room temp. —calculate ∆S A. ∆S of S(s)=321 J/K/mol, ∆S Cu(s)=33.2 J/K/mol, ∆S Cu2S(s)=120.9 J/ K/mol B. ∆Srxn=(#moles x ∆S) products - (#moles x ∆S) reactants C. ∆Srxn=-22.4 J/K D. if ∆H is positive and ∆S is negative, ∆G will always be positive under any temp. • couple this reaction with another driving reaction to make it run: S(s) + O2(g)— >SO2(g), ∆G=-300.1 kJ —Cu2S(s) + O2(g)—>2Cu(s) + SO2(g) —∆Grxn=86.2 kJ + (-300.1 kJ) —∆Grxn=-213.9 kJ, reaction is now spontaneous —no “change,” meaning extra ener
Textbook: Introductory Chemistry: A Foundation
Author: Steven S. Zumdahl, Donald J. DeCoste
Since the solution to 145 from 2 chapter was answered, more than 225 students have viewed the full step-by-step answer. This full solution covers the following key subjects: . This expansive textbook survival guide covers 21 chapters, and 2203 solutions. The answer to “The mean distance from the earth to the sun is 9.3 _ 107 mi. What is this distance in kilometers? in centimeters?” is broken down into a number of easy to follow steps, and 22 words. Introductory Chemistry: A Foundation was written by and is associated to the ISBN: 9781439049402. This textbook survival guide was created for the textbook: Introductory Chemistry: A Foundation, edition: 7. The full step-by-step solution to problem: 145 from chapter: 2 was answered by , our top Chemistry solution expert on 03/14/18, 08:03PM.