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Get Full Access to Physics: Principles With Applications - 6 Edition - Chapter 13 - Problem 36p
Get Full Access to Physics: Principles With Applications - 6 Edition - Chapter 13 - Problem 36p

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# A tank contains 26.0 kg of O2 gas at a gauge pressure of

ISBN: 9780130606204 3

## Solution for problem 36P Chapter 13

Physics: Principles with Applications | 6th Edition

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Problem 36P

Problem 36P

A tank contains 26.0 kg of O2 gas at a gauge pressure of 8.70 atm. If the oxygen is replaced by helium, how many kilograms of the latter will be needed to produce a gauge pressure of 7.00 atm?

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Solution 36PIntroductionIn this question, we shall have to consider the Poiseuille’s equation to find the pressuredifference.SolutionGiven that, length of the tube l = 2.0 mDiameter of the tube = 1.0 mmRadius of the tube r = 0.5 mmr = 0.5 × 10 3 mr = 5 × 10 4 mv avg = 4.0 m/s 0 3Viscosity of water at 40 C, = 0.7 × 10 Pa.sWe know that, volume flow of rate is Q = v avg × A , A is the cross-section of the tube.We can calculate A as follows,A = r 2 4 2 2A = 3.14 × (5 × 10 ) m 8 2A = 78.5 × 10 mTherefore, Q = v avg Pr4 8l = v avgA …..(1)Here, P = pressure differenceWe can calculate P by substituting the given values in equation (1) as shown follows. 4.0 m/s × 78.5×m × 8×0.7×103Pa.s ×2.0 mP = 44 4 3.14×(5×10) mP = 1.792 × 10 Pa5 5Therefore, the required pressure difference is 1.792 × 10 Pa.

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