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Enzymes are often described as following the two-step
Chapter , Problem 14.116(choose chapter or problem)
Enzymes are often described as following the two-step mechanism: E + S ES 1fast2 ES E + P 1slow2 where E = enzyme, S = substrate, ES = enzyme9substrate complex, and P = product. (a) If an enzyme follows this mechanism, what rate law is expected for the reaction? (b) Molecules that can bind to the active site of an enzyme but are not converted into product are called enzyme inhibitors. Write an additional elementary step to add into the preceding mechanism to account for the reaction of E with I, an inhibitor.
Questions & Answers
QUESTION:
Enzymes are often described as following the two-step mechanism: E + S ES 1fast2 ES E + P 1slow2 where E = enzyme, S = substrate, ES = enzyme9substrate complex, and P = product. (a) If an enzyme follows this mechanism, what rate law is expected for the reaction? (b) Molecules that can bind to the active site of an enzyme but are not converted into product are called enzyme inhibitors. Write an additional elementary step to add into the preceding mechanism to account for the reaction of E with I, an inhibitor.
ANSWER:Problem 14.116Enzymes are often described as following the two-step mechanism: E + S ES (fast) ES E + P (slow)where E = enzyme, S = substrate, ES = enzyme-substrate complex, and P = product.(a) If an enzyme follows this mechanism, what rate law is expected for the reaction(b) Molecules that can bind to the active site of an enzyme but are not converted into productare called enzyme inhibitors. Write an additional elementary step to add into the precedingmechanism to account for the reaction of E with I, an inhibitor. Step-by-step solution Step 1 of 3 (a)The two-step mechanism for the enzyme reaction is as follows: E + S ES (fast) ES E + P (slow)Here, E is enzyme, S is substrate, ES is enzyme-substrate complex, and P is product.For reaction having multi-steps, the slowest step is the rate determining step. Therefore, rate ofthe given enzyme reaction is e equal to k[ES], here k is rate constant.According to the first step of the mechanism: Rate of forward reaction (R ) = ForE][1 Rate of reverse reaction (R Rev= k-1ES]Here k , k are rate constants for forward and reverse reactions of the first step of the 1 -1mechanism.