Solution Found!
When a gas is taken from a to c along the curved path in
Chapter 22, Problem 12P(choose chapter or problem)
(III) When a gas is taken from a to along the curved path in Fig.
, the work done by the gas is \(W=-35 \mathrm{~J}\) and the heat added to the gas is \(Q=-63 \mathrm{~J}\). Along path abc, the work done is \(W=-48 \mathrm{~J}\).
What is
for path abc?
(b) If \(P_{c}=\frac{1}{2} P_{b}\), what is for path cda?
What is
for path cda?
What is \(U_{a}-U_{c}\)?
(e) If \(U_{d}-U_{c}=5 \mathrm{~J}\), what is for path da?
Equation Transcription:
Text Transcription:
W=-35 J
Q=-63 J
W=-48 J
P_{c}=\frac{1}{2} P_{b}
U_{a}-U_{c}
U_{d}-U_{c}=5 J
Questions & Answers
QUESTION:
(III) When a gas is taken from a to along the curved path in Fig.
, the work done by the gas is \(W=-35 \mathrm{~J}\) and the heat added to the gas is \(Q=-63 \mathrm{~J}\). Along path abc, the work done is \(W=-48 \mathrm{~J}\).
What is
for path abc?
(b) If \(P_{c}=\frac{1}{2} P_{b}\), what is for path cda?
What is
for path cda?
What is \(U_{a}-U_{c}\)?
(e) If \(U_{d}-U_{c}=5 \mathrm{~J}\), what is for path da?
Equation Transcription:
Text Transcription:
W=-35 J
Q=-63 J
W=-48 J
P_{c}=\frac{1}{2} P_{b}
U_{a}-U_{c}
U_{d}-U_{c}=5 J
ANSWER:
SolutionSolutionStep 1 of 3The speed of the wave is the ratio of the wavelength or the length of the wave to thetime period(time taken to complete one cycle),That is, v = TWhere v is the speed , is the wavelength and T is the time period.Since frequency(number of oscillations per second) is related to time period as, f = 1 T