The two systems 2x1 + x2 = 3 4x1 + 3x2 = 5 and 2x1 + x2 = 1 4x1 + 3x2 = 1 have the same coefficient matrix but different righthand sides. Solve both systems simultaneously by eliminating the first entry in the second row of the augmented matrix 2 1 3 1 4 3 5 1 and then performing back substitutions for each of the columns corresponding to the right-hand sides.

L33 - 5 Fundamental Theorem of Calculus, Part II: If f is continuous on [a,b],...