Linear systems are particularly easy to solve when they are in triangular form (i.e.
Chapter 1, Problem 40(choose chapter or problem)
Linear systems are particularly easy to solve when they are in triangular form (i.e., all entries above or below the diagonal are zero). a. Solve the lower triangular systemx\ = -3 -3jci + X2 = 1 4 *1 + 2X2 + *3 = 9 x\ + 8*2 ~ 5*3 + *4 = 33by forward substitution, finding x\ first, then *2, then *3, and finally *4. b. Solve the upper triangular system*1 + 2*2 *3 + 4x4 = -3 X2 + 3*3 -I- 7*4 = 5 *3 4- 2*4 = 2 *4 = 0
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