The machinist's square shown in Figure 53 consists of a thin, rectangular blade connected to a rectangular handle. a. Determine the ?x and y coordinates of the center or gravity. Let the lower left c? ? ner be? ? 0, y = 0. b. Sketch how the tool would hang if it were allowed to freely pivot about the ? ? point ?x = 0,? = 0. c. When hanging from that point, what angle would the long side of the blade make with the vertical? FIGURE 53

Solution A. Here we have to calculate the center of gravity of lower left corner.generally the center of gravity of two particle system is given by (x cg, cg((x m 1x 1 )/(2 +2 ),(y1m +y 2 )/(1 +1 ) 2 2 1 2 Consider center of gravity of blade and handle as (x y )and(x b band toth, henter of gravity of entire square as(x c.g, c.g Given data: Mass of the blade m = 80 g b Mass of the handle m = 40hg Using geometry of square, center of gravity of blade (8 cm,9.5 cm) Center of gravity of handle(2 cm,5.5 cm) Center of gravity of entire square is given by (xc.g,...