A 55-kg hiker starts at an elevation of 1600 m and climbs to the top of a 3300-m peak. (a) What is the hiker’s change in potential energy? (b) What is the minimum work required of the hiker? (c) Can the actual work done be more than this? Explain why.
Solution Step 1 of 4 Gravitational force is the attraction force exerted by the two objects on each other with certain masses. Which is directly proportional to the product of the masses and inversely proportional to the square of the distance between them. Example: In Solar system between sun and other planets. As shown in the figure below, G m1m 2 That is, F g r Where F is ghe gravitational force, m and m1are the 2asses of the two objects and r is 11 2 2 the distance between them. G=6.67 ×10 Nm /kg is universal gravitational constant.
Textbook: Physics: Principles with Applications
Author: Douglas C. Giancoli
This textbook survival guide was created for the textbook: Physics: Principles with Applications, edition: 6. Since the solution to 31P from 6 chapter was answered, more than 341 students have viewed the full step-by-step answer. Physics: Principles with Applications was written by and is associated to the ISBN: 9780130606204. The answer to “A 55-kg hiker starts at an elevation of 1600 m and climbs to the top of a 3300-m peak. (a) What is the hiker’s change in potential energy? (b) What is the minimum work required of the hiker? (c) Can the actual work done be more than this? Explain why.” is broken down into a number of easy to follow steps, and 50 words. This full solution covers the following key subjects: gravitational, Force, EARTH, ratio, sun. This expansive textbook survival guide covers 35 chapters, and 3914 solutions. The full step-by-step solution to problem: 31P from chapter: 6 was answered by , our top Physics solution expert on 03/03/17, 03:53PM.