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In each case, a linear transformation T : M22 M22 is defined. Give the matrix for T with
Chapter 4, Problem 1(choose chapter or problem)
In each case, a linear transformation \(T:\ M_{2\ \times\ 2} \rightarrow\ M_{2\ \times\ 2}\) is defined. Give the matrix for T with respect to the “standard basis” \(\mathbf{v}_{1}=\left[\begin{array}{ll} 1 & 0 \\ 0 & 0 \end{array}\right],\ \mathbf{v}_{2}=\left[\begin{array}{ll} 0 & 1 \\ 0 & 0 \end{array}\right],\ \mathbf{v}_{3}=\left[\begin{array}{ll} 0 & 0 \\ 1 & 0 \end{array}\right],\ \mathbf{v}_{4}=\left[\begin{array}{ll} 0 & 0 \\ 0 & 1 \end{array}\right]\) for \(M_{2\ \times\ 2}\). In each case, determine ker(T) and image (T).
a. T(X) = \(X^T\)
b. \(T(X)=\left[\begin{array}{ll} 1 & 2 \\ 3 & 4 \end{array}\right]\ X\)
c. \(T(X)=\left[\begin{array}{ll} 1 & 2 \\ 2 & 4 \end{array}\right]\ X\)
d. \(T(X)=\left[\begin{array}{ll} 1 & 2 \\ 3 & 4 \end{array}\right]\ X-X\ \left[\begin{array}{ll} 1 & 2 \\ 3 & 4 \end{array}\right]\)
Questions & Answers
QUESTION:
In each case, a linear transformation \(T:\ M_{2\ \times\ 2} \rightarrow\ M_{2\ \times\ 2}\) is defined. Give the matrix for T with respect to the “standard basis” \(\mathbf{v}_{1}=\left[\begin{array}{ll} 1 & 0 \\ 0 & 0 \end{array}\right],\ \mathbf{v}_{2}=\left[\begin{array}{ll} 0 & 1 \\ 0 & 0 \end{array}\right],\ \mathbf{v}_{3}=\left[\begin{array}{ll} 0 & 0 \\ 1 & 0 \end{array}\right],\ \mathbf{v}_{4}=\left[\begin{array}{ll} 0 & 0 \\ 0 & 1 \end{array}\right]\) for \(M_{2\ \times\ 2}\). In each case, determine ker(T) and image (T).
a. T(X) = \(X^T\)
b. \(T(X)=\left[\begin{array}{ll} 1 & 2 \\ 3 & 4 \end{array}\right]\ X\)
c. \(T(X)=\left[\begin{array}{ll} 1 & 2 \\ 2 & 4 \end{array}\right]\ X\)
d. \(T(X)=\left[\begin{array}{ll} 1 & 2 \\ 3 & 4 \end{array}\right]\ X-X\ \left[\begin{array}{ll} 1 & 2 \\ 3 & 4 \end{array}\right]\)
ANSWER:Step 1 of 8
(a)
The given matrix is
Find Ker(T) and Image(T)
The given basis are
The Equation for Kernel of T is:
Ker(T)=
The Equation for Image of T:
Image(T)=
Here, is basis of V
The Equation for Image of T is:
Image(T)