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Get Full Access to Physics: Principles With Applications - 6 Edition - Chapter 1 - Problem 4cq
Get Full Access to Physics: Principles With Applications - 6 Edition - Chapter 1 - Problem 4cq

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# A ball is dropped from the roof of a tall building and ISBN: 9780130606204 3

## Solution for problem 4CQ Chapter 1

Physics: Principles with Applications | 6th Edition

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Problem 4CQ

A ball is dropped from the roof of a tall building and students in a physics class are asked to sketch a motion diagram for this situation. A student submits the diagram shown in Figure Q1.4 . Is the diagram correct? Explain. Reference:? Figure 1.4:

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Solution 4CQ STEP 1:- The ball was dropped from a certain height and we know that it’s a free fall, means there is an acceleration which is downwards because of gravity. There is no other force except gravity acting on the ball. So let’s consider the equation of motion for a freely falling object, v = u + at ------------------(1) As the ball released at zero speed so u = 0, for this case. Acceleration a is “-g” the acceleration due to gravity. So, equation (1) will be modified as, v = gt----------------------------(2) The minus sign indicates that the ball is falling on the ground and not moving away from earth’s surface. Clearly it can be seen from eqn (2) that the velocity of the object increases as time passes. As the velocity increases so the distance covered in each second must increase gradually. STEP 2:- Let’s consider another equation of motion for the same thing, s = ut + 1/2(at )-------------------(3) Again by putting the value of “u” and “a”, we got, s = 1/2(gt )----------------------(4) The minus sign indicates again the downward motion. But the important thing to notice is, again we saw that the distance must increase every second. CONCLUSION: In the above diagram it is shown that the distance covered by the ball is clearly decreasing as time pases, which cannot be the case according to equations (2) and (4). It must increase. So the diagram is wrong.

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##### ISBN: 9780130606204

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