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The solubility of CaCO3 is pH dependent. (a) Calculate the
Chapter , Problem 17.99(choose chapter or problem)
The solubility of CaCO3 is pH dependent. (a) Calculate the molar solubility of CaCO3 1Ksp = 4.5 * 10-9 2 neglecting the acidbase character of the carbonate ion. (b) Use the Kb expression for the CO3 2 - ion to determine the equilibrium constant for the reaction CaCO31s2 + H2O1l2 Ca 2 + 1aq2 + HCO3 -1aq2 + OH-1aq2 (c) If we assume that the only sources of Ca 2 + , HCO3 -, and OH- ions are from the dissolution of CaCO3, what is the molar solubility of CaCO3 using the equilibrium expression from part (b)? (d) What is the molar solubility of CaCO3 at the pH of the ocean (8.3)? (e) If the pH is buffered at 7.5, what is the molar solubility of CaCO3?
Questions & Answers
QUESTION:
The solubility of CaCO3 is pH dependent. (a) Calculate the molar solubility of CaCO3 1Ksp = 4.5 * 10-9 2 neglecting the acidbase character of the carbonate ion. (b) Use the Kb expression for the CO3 2 - ion to determine the equilibrium constant for the reaction CaCO31s2 + H2O1l2 Ca 2 + 1aq2 + HCO3 -1aq2 + OH-1aq2 (c) If we assume that the only sources of Ca 2 + , HCO3 -, and OH- ions are from the dissolution of CaCO3, what is the molar solubility of CaCO3 using the equilibrium expression from part (b)? (d) What is the molar solubility of CaCO3 at the pH of the ocean (8.3)? (e) If the pH is buffered at 7.5, what is the molar solubility of CaCO3?
ANSWER:Problem 17.99
The solubility of is pH dependent. (a) Calculate the molar solubility of 1 2 neglecting the acid base character of the carbonate ion. (b) Use the Kb expression for the CO3 2 - ion to determine the equilibrium constant for the reaction
(c) If we assume that the only sources of Ca 2 + , HCO3 -, and OH- ions are from the dissolution of , what is the molar solubility of using the equilibrium expression from part (b)? (d) What is the molar solubility of at the pH of the ocean (8.3)? (e) If the pH is buffered at 7.5, what is the molar solubility of ?
Step by Step Solution
Step 1 of 5
Molar solubility is the number of moles of a substance that can be dissolved per liter of the solution before the solution becomes saturated. Its S.I Unit is mol / L.
Solubility Product constant is the equilibrium between a solid and its respective ions in a solution. The value of constant identifies the degree to which the compound can dissociate in water. Higher the solubility product constant more soluble the compound is.
It can be calculated as follows;
Applying law of mass action,
pOH is a measure of hydroxide ion concentration of a solution. It is calculated as follows;
a)
Molar solubility of a substance is the number of that substance dissolved in one liter of the
solution.
A small molar solubility value means the substance is partially or sparingly soluble. Now, write the equation for dissociation of calcium carbonate, .
Then for the above equilibrium is given by the relation;
The ratio between and and that between and would be 1: 1 This implies that the solution contains same amount of and
Thus, the molar solubility of carbonate ion, x is
Therefore, the molar solubility of is .