×
Log in to StudySoup
Get Full Access to Linear Algebra With Applications - 4 Edition - Chapter 3.4 - Problem 25
Join StudySoup for FREE
Get Full Access to Linear Algebra With Applications - 4 Edition - Chapter 3.4 - Problem 25

Already have an account? Login here
×
Reset your password

In Exercises 25 through 30, find the matrix B of the linear transformation with respect

Linear Algebra with Applications | 4th Edition | ISBN: 9780136009269 | Authors: Otto Bretscher ISBN: 9780136009269 434

Solution for problem 25 Chapter 3.4

Linear Algebra with Applications | 4th Edition

  • Textbook Solutions
  • 2901 Step-by-step solutions solved by professors and subject experts
  • Get 24/7 help from StudySoup virtual teaching assistants
Linear Algebra with Applications | 4th Edition | ISBN: 9780136009269 | Authors: Otto Bretscher

Linear Algebra with Applications | 4th Edition

4 5 1 334 Reviews
24
1
Problem 25

In Exercises 25 through 30, find the matrix B of the linear transformation with respect to the basis

Step-by-Step Solution:
Step 1 of 3

L'Hospital's Rule Find lim(​ln(x) x−1 x→0 As x→1, ln(x)→0 and (x-1) → 0 This is called an indeterminate form of type 0/0 Now consider lim (ln(x)) x−1 x→ ∞ As x→ ∞ ​ln(x)→ ∞ ​ nd (x-1) →∞ ​ndeterminate form of type∞ / ∞ L'Hospital's rule If f(x) and g(x) are both differentiable and / 0a) = suppose that lim(f(x)) = 0 and lim(g(x)) = 0 x→a x→a Or that lim(f(x))∞= ​ nd lim(g(x)) ∞ x→a x→a f(x) f′(x) Then lim (g(x) ) ​ lim(g′x)) x→a x→a Note: This is not the quotient rule take f’(x) and g’(x) separately Ex. Find lim(ln(x)/(x-1)) = lim((1/x)/1) = lim(x/1) = 1/1 = 1 x→1 x→1 x→1 Ex. Find lim(ln(x)/(x-1)) = lim(1/x) = 0 x→

Step 2 of 3

Chapter 3.4, Problem 25 is Solved
Step 3 of 3

Textbook: Linear Algebra with Applications
Edition: 4
Author: Otto Bretscher
ISBN: 9780136009269

Other solutions

People also purchased

Related chapters

Unlock Textbook Solution

Enter your email below to unlock your verified solution to:

In Exercises 25 through 30, find the matrix B of the linear transformation with respect