When expressing molarity, M stands for (A) atoms per liter of water. (B) moles per milliliter of solvent. (C) moles per liter of solution. (D) atoms per milliliter of solute. (E) grams per liter of solution.
MolarRelationshipsinreactionequations Take this example: 4HCl + 1O 2 à 2Cl 2+ 2H 2 O • Ratio of coefficients (stoichiometry) = 4:1:2:2 Q1: 6 mols of HCL will react w/ how many mol2of O o Based on the ratio, one mole 2is equal to 4.00 mols of HCl, so you’d multiply : (1 mol of O2 / 4.00 mols of HCl ) X 6.0 mol HCl = 1.2 mol of O Take another example: CaCN 2 + 3H 2O à CaCO 3 + 2NH 3 • Ratio: 1: 3: 1: 2 Q: How many g of 2O are needed to react w/ 75.0 g of2aCN o A way to figure out how and where to start it is using this step by step formula: § Use mass given and divide it by the molar mass o2 ( which is 80.11 g/mol) à this will give you the amount of mole2
