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Classify each of the following reactions as one of the
Chapter , Problem 19.65(choose chapter or problem)
Classify each of the following reactions as one of the four possible types summarized in Table 19.3: (i) spontanous at all temperatures; (ii) not spontaneous at any temperature; (iii) spontaneous at low T but not spontaneous at high T; (iv) spontaneous at high T but not spontaneous at low T. (a) N21g2 + 3 F21g2 2 NF31g2 H = -249 kJ; S = -278 J>K (b) N21g2 + 3 Cl21g2 2 NCl31g2 H = 460 kJ; S = -275 J>K (c) N2F41g2 2 NF21g2 H = 85 kJ; S = 198 J>K
Questions & Answers
QUESTION:
Classify each of the following reactions as one of the four possible types summarized in Table 19.3: (i) spontanous at all temperatures; (ii) not spontaneous at any temperature; (iii) spontaneous at low T but not spontaneous at high T; (iv) spontaneous at high T but not spontaneous at low T. (a) N21g2 + 3 F21g2 2 NF31g2 H = -249 kJ; S = -278 J>K (b) N21g2 + 3 Cl21g2 2 NCl31g2 H = 460 kJ; S = -275 J>K (c) N2F41g2 2 NF21g2 H = 85 kJ; S = 198 J>K
ANSWER:Problem 19.65(i) spontaneous at all temperatures; (ii) not spontaneous at any temperature; (iii) spontaneous atlow T but not spontaneous at high T; (iv) spontaneous at high T but not spontaneous at low T.Classify each of the following reactions as one of the four possible types summarized in Table19.3:(a) N (g) + 3 F (g) 2 NF (g) H° = -249 kJ; S° = -278 J/K 2 2 3(b) N 2) + 3 Cl (2 2 NCl (g) H3= 460 kJ; S° = -275 J/K(c) N F (g) 2 NF (g) H° = 85 kJ; S° = 198 J/K 24 2 Step-by-step solution Step 1 of 3 (a) N 2) + 3F (g2 2NF (g) 3 H°= 249 KJ, S = 278 J/K G°= H° TS° G°is negative at law T and positive at high T. Spontaneous at low T becomes non spontaneous at high temperature.