Show that the energy E (in electron volts) of a photon

Chapter 27, Problem 29

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Show that the energy \(E\) (in electron volts) of a photon whose wavelength is \(\lambda\) (nm) is given by \(E=\frac{1.240 \times 10^3~\mathrm{eV \cdot nm}} {\lambda~ \mathrm{(nm)}}\). Use at least 4 significant figures for values of \(h\), \(c\), \(e\) (see inside front cover).

Equation Transcription:

Text Transcription:

E=frac{1.240 x 10^3 eV cdot nm} {lambda (nm)}

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