The Scottish mathematician James Stirling found an approximation formula for n
Chapter 9, Problem 9.7(choose chapter or problem)
The Scottish mathematician James Stirling found an approximation formula for n. Stirlings formula is n p 2 nnn e n where D 3:14159 : : : and e D 2:71828 : : :. (Scientific calculators have a key that computes e x ; this key might be labeled exp x .) Compute n and Stirlings approximation to n for n D 10; 20; 30; 40; 50. What is the relative error in the approximations?
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