Suppose that Y is a binomial random variable based on n trials with success probability
Chapter 3, Problem 3.54(choose chapter or problem)
Suppose that Y is a binomial random variable based on n trials with success probability p and consider Y = n Y . a Argue that for y = 0, 1,..., n P(Y = y ) = P(n Y = y ) = P(Y = n y ). b Use the result from part (a) to show that P(Y = y ) = n n y pny qy = n y qy pny . c The result in part (b) implies that Y has a binomial distribution based on n trials and success probability p = q = 1 p. Why is this result obvious? 3.
Unfortunately, we don't have that question answered yet. But you can get it answered in just 5 hours by Logging in or Becoming a subscriber.
Becoming a subscriber
Or look for another answer