Solved: In Exercise 5.10, we proved that f (y1, y2) = 1, 0 y1 2, 0 y2 1, 2y2 y1, 0

Chapter 5, Problem 5.54

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In Exercise 5.10, we proved that f (y1, y2) = 1, 0 y1 2, 0 y2 1, 2y2 y1, 0, elsewhere is a valid joint probability density function for Y1, the amount of pollutant per sample collected above the stack without the cleaning device, and Y2, the amount collected above the stack with the cleaner. Are the amounts of pollutants per sample collected with and without the cleaning device independent?

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