In Exercise 5.8, we established that f (y1, y2) = 4y1 y2, 0 y1 1, 0 y2 1, 0, elsewhere
Chapter 5, Problem 5.105(choose chapter or problem)
In Exercise 5.8, we established that f (y1, y2) = 4y1 y2, 0 y1 1, 0 y2 1, 0, elsewhere is a valid joint probability density function. In Exercise 5.52, we established that Y1 and Y2 are independent; in Exercise 5.76, we determined that E(Y1 Y2) = 0 and found the value for V(Y1). Find V(Y1 Y2).
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