In Exercise 5.9, we determined that f (y1, y2) = 6(1 y2), 0 y1 y2 1, 0, elsewhere is a valid joint probability density function. In Exercise 5.76, we derived the fact that E(Y13Y2) = 5/4; in Exercise 5.92, we proved that Cov(Y1, Y2) = 1/40. Find V(Y13Y2).

Chapter1 WhatisStatistics Itisadisciplineandawaytocollectdata/information § Datacanbenumbers(weight,income,height)oritcouldbewords(gender,race,favoritecolor) Variability :Theextenttowhichdatapointsinastatisticaldistributiondivergefromtheaverage...