Get answer: In Exercise 5.9, we determined that f (y1, y2) = 6(1 y2), 0 y1 y2 1, 0
Chapter 5, Problem 5.133(choose chapter or problem)
In Exercise 5.9, we determined that f (y1, y2) = 6(1 y2), 0 y1 y2 1, 0, elsewhere is a valid joint probability density function. a Find E(Y1|Y2 = y2). b Use the answer derived in part (a) to find E(Y1). (Compare this with the answer found in Exercise 5.77.)
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