If Y is a continuous random variable and m is the median of the distribution, then m is

Chapter 6, Problem 6.82

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If Y is a continuous random variable and m is the median of the distribution, then m is such that P(Y m) = P(Y m) = 1/2. If Y1, Y2,..., Yn are independent, exponentially distributed random variables with mean and median m, Example 6.17 implies that Y(n) = max(Y1, Y2,..., Yn ) does not have an exponential distribution. Use the general form of FY(n) (y) to show that P(Y(n) > m) = 1 (.5)n .

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