Let S2 1 denote the sample variance for a random sample of ten ln(LC50) values for

Chapter 7, Problem 7.36

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QUESTION:

Let S2 1 denote the sample variance for a random sample of ten ln(LC50) values for copper and let S2 2 denote the sample variance for a random sample of eight ln(LC50) values for lead, both samples using the same species of fish. The population variance for measurements on copper is assumed to be twice the corresponding population variance for measurements on lead. Assume S2 1 to be independent of S2 2 . a Find a number b such that P S2 1 S2 2 b = .95. b Find a number a such that P a S2 1 S2 2 = .95. [Hint: Use the result of Exercise 7.29 and notice that P(U1/U2 k) = P(U2/U1 1/k).] c If a and b are as in parts (a) and (b), find P a S2 1 S2 2 b .

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QUESTION:

Let S2 1 denote the sample variance for a random sample of ten ln(LC50) values for copper and let S2 2 denote the sample variance for a random sample of eight ln(LC50) values for lead, both samples using the same species of fish. The population variance for measurements on copper is assumed to be twice the corresponding population variance for measurements on lead. Assume S2 1 to be independent of S2 2 . a Find a number b such that P S2 1 S2 2 b = .95. b Find a number a such that P a S2 1 S2 2 = .95. [Hint: Use the result of Exercise 7.29 and notice that P(U1/U2 k) = P(U2/U1 1/k).] c If a and b are as in parts (a) and (b), find P a S2 1 S2 2 b .

ANSWER:

Step 1 of 4

Given data

For n=10 samples of ln(LC50) values of copper

Sample variance is

For n=8 samples of ln(LC50) values of lead

Samples variance is

We are also given that

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