An express train passes through a station. It enters with an initial velocity of 22.0 m/s and decelerates at a rate of 0.150 m/s2 as it goes through. The station is 210 m long. (a) How long is the nose of the train in the station? (b) How fast is it going when the nose leaves the station? (c) If the train is 130 m long, when does the end of the train leave the station? (d) What is the velocity of the end of the train as it leaves?

Step-by-step solution 36PE Step 1 of 6 The train is decelerating and will achieve some final velocity as it leaves the station. Therefore, the final velocity of the car can be calculated by using the below formula. Here, a is the acceleration of the train, s is the length of the pla tform and u is the initial velocity of train. Step 2 of 6 (a) The velocity of train as it leaves the station is, Substitute 22 m/sfor u , for a and 210 m for s. Step 3 of 6 The time t it takes by train to cross the station is calculated as, Substitute for v , for a and 22 m/s for u. Hence, the train’s nose will remain for on the station.