Dragsters can actually reach a top speed of 145 m/s in only 4.45 s—considerably less time than given in Example 2.10 and Example 2.11. (a) Calculate the average acceleration for such a dragster. (b) Find the final velocity of this dragster starting from rest and accelerating at the rate found in (a) for 402 m (a quarter mile) without using any information on time. (c) Why is the final velocity greater than that used to find the average acceleration? Hint: Consider whether the assumption of constant acceleration is valid for a dragster. If not, discuss whether the acceleration would be greater at the beginning or end of the run and what effect that would have on the final velocity. Example 2.10: Calculating Displacement of an Accelerating Object: Dragsters Dragsters can achieve average accelerations of 26.0 m/s2 . Suppose such a dragster accelerates from rest at this rate for 5.56 s. How far does it travel in this time? Example 2.11: Calculating Final Velocity: Dragsters Calculate the final velocity of the dragster in Example 2.10 without using information about time.

Step-by-step solution 37PE Step 1 of 5 (a) The formula to find the average acceleration is, Here is the final speed, is the initial speed, is the time. Step 2 of 5 The average acceleration of the dragster is, Substitute for , for and for Hence, the average acceleration of the dragster is . Step 3 of 5 (b) The formula to find the final velocity of the square is, Substitute for , for and for . The final velocity of the dragster is,