The AS for the reaction shown, at 298.15 K, is 0.003 00 kJ/(mol.'K). Calculate the i.G
Chapter 16, Problem 28(choose chapter or problem)
The AS for the reaction shown, at 298.15 K, is 0.003 00 kJ/(mol.'K). Calculate the i.G for this reaction, and determine whether it will occur spontaneously at 298.15 K. C(s) + 02(g) - CO2(9) + 393.51 kJ
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