You throw a ball straight up with an initial velocity of 15.0 m/s. It passes a tree branch on the way up at a height of 7.00 m. How much additional time will pass before the ball passes the tree branch on the way back down?
Step-by-step solution 49PE Step 1 of 3 The ball passes the same tree branch twice in this case. First time it passes that point while moving upwards and the second time when it returns back after attaining a maximum height. Step 2 of 3 The initial speed of the ball is 15.0 m/s as it is thrown upwards. The initial position of the ball o is 0 m as it was thrown from ground level and the final position of the bally is 7 m. The acceleration of the ball is . From the formula, The equatio n is quadratic in time t and on solving gives, Substitute 7 m for yo, 0 m for y , for and for . The time t1 is 0.57 s is the time at which ball pass that point while moving upwards. The time t 2 is 2.49 s is the time at which ball pass that point while moving downwards.