An object is dropped from a height of 75.0 m above ground level. (a) Determine the distance traveled during the first second. (b) Determine the final velocity at which the object hits the ground. (c) Determine the distance traveled during the last second of motion before hitting the ground.
Step-by-step solution 52PE Step 1 of 5 If the initial po sitio o of the object is the reference point, then the initial position of the object is 0 m and the final p osition of the object is . The initial velocity of the body is zero. The acceleration of the body is . Step 2 of 5 (a) The displacement of the body is, Substitute 0 m/s for u, 1.0 s for nd for . Hence, it traveled a distance of in 1 s. Step 3 of 5 (b) From the equation of motion, The final velocity of the object is, Substitute 0 m/s for u, for s and for a . The final velocity will be negative as object is falling downwards. Hence, the velocity at which the object hits the ground is .