A steel ball is dropped onto a hard floor from a height of 1.50 m and rebounds to a height of 1.45 m. (a) Calculate its velocity just before it strikes the floor. (b) Calculate its velocity just after it leaves the floor on its way back up. (c) Calculate its acceleration during contact with the floor if that contact lasts 0.0800 ms (8.00×10?5 s) . (d) How much did the ball compress during its collision with the floor, assuming the floor is absolutely rigid?

Step-by-step solution 56PE Step 1 of 9 (a) The formula to find the final velocity is, Here is the final speed, is the initial speed, is the acceleration. Step 2 of 9 Substitute for , for and for Step 3 of 9 Therefore, The velocity is negative as the ball is falling downwards. Hence, its velocity just before it strikes the floor is . Step 4 of 9 (b) The formula to find the final velocity is, Step 5 of 9 Substitute for , for and for