Normal octane at 68 F ( = 8.31 106 ft2/s) is to bedelivered at a flow rate of 3.0
Chapter 8, Problem 8.114(choose chapter or problem)
Normal octane at 68 F ( = 8.31 106 ft2/s) is to bedelivered at a flow rate of 3.0 gal/min through a 2.0-in. schedule40 commercial steel pipe(with an actual inside diameter of 2.067 in.). Energy losses areimportant, so consideration is being given to expanding the pipe toa 3.0-in. schedule 40 commercial steel pipe (with an actual insidediameter of 3.068 in.), using a 10 conical expansion. After alength of the 3.0-in. pipe, it is decreased to a 2.0-in. schedule 40commercial steel pipe with a gradual contraction (K = 0.10, basedon the smaller diameter pipe flow). Find the minimum length sothat the energy loss will be the same as in a 2.0-in. pipe of length + 2 (5.7 in.) See Fig. P8.114.
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