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Solved: In the previous exercise, all infected individuals remained in the population to

Numerical Analysis | 10th Edition | ISBN: 9781305253667 | Authors: Richard L. Burden J. Douglas Faires, Annette M. Burden ISBN: 9781305253667 457

Solution for problem 6 Chapter 5.5

Numerical Analysis | 10th Edition

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Numerical Analysis | 10th Edition | ISBN: 9781305253667 | Authors: Richard L. Burden J. Douglas Faires, Annette M. Burden

Numerical Analysis | 10th Edition

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Problem 6

In the previous exercise, all infected individuals remained in the population to spread the disease. A more realistic proposal is to introduce a third variable z{t) to represent the number of individuals who are removed from the affected population at a given time t by isolation, recovery and consequent immunity, or death. This quite naturally complicates the problem, but it can be shown (see [Ba2]) that an approximate solution can be given in the form x{t) = x(0)e_(* l//:2):(' ) and y(t) = m - x(t) - z(t), where k\ is the infective rate, ki is the removal rate, and zit) is determined from the differential equation z'(t) = k2 (m - z(t) - x(0)e-{ki,k2M,)). The authors are not aware of any technique forsolving this problem directly, so a numerical procedure must be applied. Find an approximation to z(30), >'(30), and x(30), assuming that m 100,000, x{0) = 99,000, k\ = 2x lO"6 , and k2 = IQ-4 .

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Macromolecules Macromolecules = small organic molecules joined together to form larger molecules  There are four major classes of macromolecules (small organic molecules joined together to form larger molecules): o Carbohydrates, lipids, proteins, and nucleic acids Polymer = a long molecule consisting of many monomers Monomer = the smaller repeating units of polymers Carbohydrates:  Carbs = sugars  The simplest carbohydrates are monosaccharides o Disaccharides = two monosaccharides  Ex. Maltose, sucrose, lactose o Polysaccharides = polymers of many monosaccharides  Ex. Starch, glycogen, cellulose, chitin

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Chapter 5.5, Problem 6 is Solved
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Textbook: Numerical Analysis
Edition: 10
Author: Richard L. Burden J. Douglas Faires, Annette M. Burden
ISBN: 9781305253667

This textbook survival guide was created for the textbook: Numerical Analysis, edition: 10. The full step-by-step solution to problem: 6 from chapter: 5.5 was answered by , our top Math solution expert on 03/16/18, 03:24PM. The answer to “In the previous exercise, all infected individuals remained in the population to spread the disease. A more realistic proposal is to introduce a third variable z{t) to represent the number of individuals who are removed from the affected population at a given time t by isolation, recovery and consequent immunity, or death. This quite naturally complicates the problem, but it can be shown (see [Ba2]) that an approximate solution can be given in the form x{t) = x(0)e_(* l//:2):(' ) and y(t) = m - x(t) - z(t), where k\ is the infective rate, ki is the removal rate, and zit) is determined from the differential equation z'(t) = k2 (m - z(t) - x(0)e-{ki,k2M,)). The authors are not aware of any technique forsolving this problem directly, so a numerical procedure must be applied. Find an approximation to z(30), >'(30), and x(30), assuming that m 100,000, x{0) = 99,000, k\ = 2x lO"6 , and k2 = IQ-4 .” is broken down into a number of easy to follow steps, and 159 words. Numerical Analysis was written by and is associated to the ISBN: 9781305253667. Since the solution to 6 from 5.5 chapter was answered, more than 231 students have viewed the full step-by-step answer. This full solution covers the following key subjects: . This expansive textbook survival guide covers 76 chapters, and 1204 solutions.

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Solved: In the previous exercise, all infected individuals remained in the population to