Suppose a wolf is chasing a rabbit. The path ofthe wolftoward the rabbit is called a curve of pursuit. Assume the wolf runs at the constant speed a and the rabbit at the constant speed /I. Let the wolf begin at time / = 0 at the origin and the rabbit at the point (0, 1). Assume the rabbit runs up the line x = 1. Let (x(t), y(t)) denote the position ofthe wolf attime t. The differential equation describing the curve of pursuit is ax 2 Suppose the wolf runs at the speed 35 miles per hour and the rabbit runs at the speed 25 miles per hour. Find the location (x(/), y{t)) where the wolf catches the rabbit using the Extrapolation method with TOL = 1()-|H , hmin = KT12 , and hmax =0.1.

M303 Section 1.5 Notes- Solution Sets of Linear Systems 9-12-16 equations would have much more variancee much variety; general system of algebraic Homogeneous system- can be written in matrix form as A x=0 , ie. right sides of all equations are 0 o Can simply row reduce A - no operations will change augmented column when it is0 o Always consistent-...