Problem 19Q

Problem

A projectile is launched at an upward angle of 30° to the horizontal with a speed of 30 m/s How does the horizontal component of its velocity 1.0 s after launch compare with its horizontal component of velocity 2.0 s after launch, ignoring air resistance? Explain.

Problem 19Q

Step-by-step solution

Step 1 of 1

Angle made with horizontal = 30°

Initial speed of ball = 30 m/s

Time = 1 secs.

Horizontal component of

In the horizontal direction, there is no acceleration. Therefore, the horizontal component of the velocity remains constant and has the same value at each point on its trajectory.

Only the vertical component would be accelerated due to gravity.

Evidently, the horizontal component of velocity after 2 s is also 26 m/s.